x^2+59x+564=0=0

Solution for x^2+59x+564=0=0 equation:

x^2+59x+564=0=0

a = 1; b = 59; c = +564;
Δ = b2-4ac
Δ = 592-4·1·564
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(59)-35}{2*1}=\frac{-94}{2}
=-47
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(59)+35}{2*1}=\frac{-24}{2}
=-12
$